Index lifting theorem in elementary number theory
index lifting theorem in elementary number theory 初等数论中的指数提升定理
Index lifting theorem in elementary number theory Read MoreTag: number theory
Yitang Zhang is giving the last invited talk at ICM 2014: Small gaps between primes and primes in arithmetic progressions to large moduli
Yitang Zhang is giving the last invited talk at ICM 2014, “Small gaps between primes and primes in arithmetic progressions to large moduli”. 这是闭幕式前的最后一个 invited talk. 张大师习惯手写, 当场演算. Yitang Zhang …
Yitang Zhang is giving the last invited talk at ICM 2014: Small gaps between primes and primes in arithmetic progressions to large moduli Read MoreManjul Bhargava: The Musical, Magical Number Theorist
Manjul Bhargava, 昨天上午在第二十七届国际数学家大会(ICM 2014)开幕式上, 从韩国总统朴槿惠手中接过菲尔兹奖章. References Erica Klarreich, The Musical, Magical Number Theorist, August 12, 2014
Manjul Bhargava: The Musical, Magical Number Theorist Read MoreYitang Zhang’s talks in the summer of 2014 in Beijing
ICM 2014 Program 这届国际数学界大会(International Congress of Mathematicians, ICM)的安排, 已经明确无误的说明: 4 个数学家将获得本届大会的 Fields Medal. 张大师将于 8 月 21 日作 ICM 闭幕式之前的压轴报告, 这是只有今年的 Fields Medalist, Gauss Prize, Chern Medal 得主才有的殊荣 张益唐 7 月1 日在北大本科生毕业典礼有一个讲话 这个暑假, …
Yitang Zhang’s talks in the summer of 2014 in Beijing Read MoreNumber Theory in the Spirit of Liouville
I’ve just received a book named Number Theory in the Spirit of Liouville by Kenneth S. Williams. Joseph Liouville is recognised as one of the great mathematicians of the nineteenth century, …
Number Theory in the Spirit of Liouville Read MoreDevelopment of Elliptic Functions According to Ramanujan
I’ve just received a book named Development of Elliptic Functions According to Ramanujan by K Venkatachaliengar (deceased) , edited by: ShaunCooper , Shaun Cooper This unique book provides an innovative …
Development of Elliptic Functions According to Ramanujan Read MoreIntegers represented by \(a^3+b^3+c^3-3abc\)
Which integers can be expressed as \(a^3+b^3+c^3-3abc\)? \(a\), \(b\), \(c\in\Bbb Z\). \[(a\pm1)^3+a^3+a^3-3(a\pm1)a^2=3a\pm1\] \[(a-1)^3+a^3+(a+1)^3-3a(a+1)(a-1)=9a\] \[2(a^3+b^3+c^3-3abc)=3(a+b+c)(a^2+b^2+c^2)-(a+b+c)^3\] If \(3\mid(a^3+b^3+c^3-3abc)\), then \(3\mid(a+b+c)^3\), \(3\mid(a+b+c)\). so \(9\mid(a^3+b^3+c^3-3abc)\). All \(n\) such that \(3\nmid n\) or \(9\mid n\).
Integers represented by \(a^3+b^3+c^3-3abc\) Read MoreActa Arithmetica
Acta Arithmetica(ISSN: 0065-1036(print) 1730-6264(online)) is a scientific journal of mathematics publishing papers on number theory. It was established in 1935 by Salomon Lubelski and Arnold Walfisz. The journal is published …
Acta Arithmetica Read More